Theory · topic 5 of 10 · 8 min

Sun sights

A timed sun sight gives one position line. The intercept, the difference between the altitude you measured and the one calculated for a known point, places it.

1 · The sight

Altitude and time, both exact

How accurately do I need to time a sun sight?

To the second: 4 seconds of time is 1′ of longitude. Turn the watch time into UT by removing its error and adding the zone description, and watch for a change of Greenwich date.

Take the Sun above about 15°, where refraction is steady; well east or west, its line runs near north–south and fixes longitude. Time it to the second: 4 seconds is 1′ of longitude.

Turn the watch into UT: remove its error, add the zone description (positive in west zones); past 2400 or below 0000 the Greenwich date and the almanac page change.

Hs to Ho: index error, dip, then the main correction.

Ho is Hs corrected for index error, dip and the main correction for your limb and season. In a seaway take several sights and average them, dropping any out of step.

2 · Almanac

GHA, declination and LHA

Is the LHA over or under 180° for a morning sun sight?

Over 180°: in the morning the Sun is east of you. LHA = GHA − west longitude or + east longitude, adding or taking off 360°; in the afternoon it is under 180°.

The daily page gives the Sun's GHA and Dec for each hour of UT. Add the increment for the minutes and seconds (the Sun moves 15° an hour) and correct Dec with d, checking the next hour for its trend; near an equinox its name can change.

LHA is the Sun's angle west of your meridian: GHA minus west longitude or plus east, with 360° added or taken off. Morning, the Sun east of you: LHA over 180°. Afternoon: under 180°.

LHA in west longitude
  • GHA Sun at 14h 031°10.0′
  • Increment 20m 00s +5°00.0′
  • GHA 036°10.0′
  • 36°10.0′ + 360° − 81°10.0′ W
  • LHA 315°: morning, Sun to the east
Rule

LHA = GHA − longitude west, + longitude east.

3 · Hc and Zn

Solving the PZX triangle

How do I choose the assumed position for an HO 249 sight reduction?

Take the nearest whole degree of latitude and a longitude within 30′ of the DR that makes LHA whole: that is the assumed position. In west longitude its minutes are the GHA's, in east 60′ minus them.

Pole, zenith and Sun make a triangle. You know two sides, 90° − Lat and 90° − Dec, and the angle between them at the pole, the LHA. Solving it gives 90° − Hc, the altitude seen from that position, and the azimuth.

Angle at P: the LHA. Angle at Z: the azimuth.

By calculator, sin Hc = sin Lat sin Dec + cos Lat cos Dec cos LHA, a contrary-name Dec negative, from any position: use the DR.

HO 249 tabulates whole degrees, so you work from an assumed position: the nearest whole degree of latitude, and a longitude within 30′ of the DR longitude that makes LHA whole (in west longitude the GHA's minutes, in east 60′ minus them). Enter the same- or contrary-name page with the whole degree of Dec, correct Hc with d. Both workings plot the same line.

LatitudeLHA over 180°LHA under 180°
NorthZn = ZZn = 360° − Z
SouthZn = 180° − ZZn = 180° + Z
4 · Intercept

From two altitudes to a line

Do I plot the intercept towards or away from the Sun?

Towards if Ho is greater than Hc, away if Hc is greater. The intercept, Ho − Hc, is 1′ for 1 mile, laid off from the AP along Zn, or its reciprocal if away.

The intercept is Ho − Hc, 1′ for 1 mile. Ho greater: you are nearer the Sun than the point you worked from, towards. Hc greater: away.

  • Lay off the intercept from the AP or DR along Zn if towards, its reciprocal if away.
  • Draw the position line there, at right angles to the azimuth.
  • Measure miles on the latitude scale.

A nil intercept puts the line through the AP. A very long one is not wrong, but the line is only a short piece of a large circle: rework from a point on it. One line is not a fix; its point nearest the DR is your best position. Current matters only when a line is carried forward.

Remember

Ho greater: towards. Hc greater: away, in either hemisphere.

5 · Running fix

Sun, run, sun

How long should I wait between sun sights for a running fix?

Until the Sun's azimuth has changed about 45°, and no longer: every hour adds run error. Then carry the earlier line forward by the run to meet the later one.

The Sun gives a fix once its bearing has changed. Carry the earlier line forward by the run, course and distance made good, leeway allowed and legs added as vectors; it keeps its direction and meets the later line, or the noon latitude, at the fix.

The lines cut at the change of azimuth: wait until it has changed about 45°, and no longer than that: every hour adds run error. Add a known current to the run; an unknown one shows afterwards as the gap from DR to fix. In the tropics the azimuth swings so fast past noon that sights an hour apart cut well.

Around its quarters the Moon is up by day: Sun and Moon lines taken together cross with no run.

6 · One line

What one line tells you

What does a sun line tell me when the Sun is abeam?

Your offset from the track: with the Sun abeam the position line is a course line. Ahead or astern it is a speed line, giving distance run; due east or west, a meridian giving longitude.

A position line lies at right angles to the Sun's bearing: pick the moment to suit the question.

Sun bearsThe line shows
AbeamCourse line: your offset from the track
Ahead or asternSpeed line: distance run
Due east or westA meridian: longitude
Square to a coast or reefDistance off it

Along the reef: 14.0 M from the AP less 5.2 M towards leaves 8.8 M off.

It also crosses a depth contour where the bottom rises steeply, or a radar range, whose circle cuts it twice; the DR says which cut is yours.

7 · Errors

A mile for a minute

Why don't my three sun lines from one day meet in a point?

Mostly because of the runs that carried the earlier lines: they make the cocked hat. A constant error shifts every line the same way; you are inside the triangle only if the azimuths span more than 180°.

SlipEffect
1′ of altitude1 mile along the azimuth
4 s of time1′ of longitude; a fast watch puts you west
Yesterday's DecA shift of the day's change in Dec
Wrong name for Lat or DecAn intercept of hundreds of miles
Error in the runMoves a carried line by its part along the azimuth

Three sun lines from one day seldom meet in a point; the cocked hat comes mostly from the runs that carried the earlier lines. A constant error shifts every line the same way along its azimuth: you are inside the triangle only if the azimuths span more than 180°. Lines a mile the same way every day betray such an error.

Practice questions

Questions from this topic, as the app asks them. Open one to see the answer.

Sun, 28 Nov, DR 17°20′N 38°45′W
  • 0715 LMT · altitude 13° · Zn 117°
  • 0845 LMT · altitude 31° · Zn 129°
  • 1145 LMT · altitude 51° · Zn 179°
  • 1215 LMT · altitude 51° · Zn 190°

Your DR longitude is in doubt after two days of cloud. At which of these times does a sun sight do most for your longitude?

  1. 1145 — the Sun is highest, so the sight is most accurate
  2. 0845 — the Sun is well clear of the meridian and above 15°
  3. 0715 — the Sun is nearest east, so the line is nearest north–south
  4. 1215 — just after noon, when the Sun's bearing is steady
Show the answer

B. 0845 — the Sun is well clear of the meridian and above 15°

A line lies at right angles to the azimuth, so a Sun well east or west of the meridian gives longitude; below 15° refraction is large and uncertain.

Sun sights — choosing the time · Explained in: The sight

Almanac, 28 November 2026
  • Sight at 14h 23m 17s UT
  • GHA Sun at 14h: 033°00.4′
  • Sun increments: 15° per hour

You work an afternoon sight on the ARC route. What is the Sun's GHA at the moment of the sight?

  1. 038°50.6′
  2. 038°49.7′
  3. 038°48.0′
  4. 027°11.1′
Show the answer

B. 038°49.7′

23m 17s at 15° an hour = 5°49.3′; 33°00.4′ + 5°49.3′ = 38°49.7′.

Sight reduction — GHA and increments · Explained in: Almanac

Sun sight, ARC route
  • AP 17°00′N 38°41.6′W
  • GHA Sun 352°41.6′
  • Dec S21°18.4′

You work this ARC morning sight by calculator from the AP. What Hc do you get?

  1. 40°52.2′
  2. 30°50.5′
  3. 46°28.8′
  4. 60°05.4′
Show the answer

B. 30°50.5′

LHA = 352°41.6′ − 38°41.6′ = 314°; Dec S is negative against a north latitude: sin Hc = sin L sin D + cos L cos D cos LHA → 30°50.5′.

Sight reduction — Hc and Zn · Explained in: Hc and Zn

Morning sun sight
  • 0945 ship's time, Sun's lower limb
  • Reduced from the DR as the AP
  • Intercept 3.1 M towards, Zn 128°

You are 600 miles west of the Canaries on the ARC route and have just reduced this sight. What does it give you?

  1. A position line running 038°–218°, not a fix
  2. Your latitude, as the Sun is still rising
  3. A position line along 128° through the DR
  4. A fix 3.1 M from the DR along 128°
Show the answer

A. A position line running 038°–218°, not a fix

One sight gives one position line, at right angles to the azimuth: 128° ± 90° = 038°/218°. A fix needs a second line.

Sun sights — the position line · Explained in: Intercept

Sun due west, June
  • DR 36°40′N 52°15.0′W (as AP)
  • Intercept 6.0 M towards
  • Zn 270°

Your afternoon sight, 600 miles east of Bermuda, has the Sun exactly due west. Combined with the noon latitude, what does it give you?

  1. Longitude 52°07.5′W
  2. Longitude 52°22.5′W
  3. Longitude 52°21.0′W
  4. Longitude 52°09.0′W
Show the answer

B. Longitude 52°22.5′W

Sun due west: the line runs north–south, a meridian. 6.0 M west at 36°40′N = 6.0 / cos 36.7° = 7.5′ of longitude: 52°22.5′W.

Sun sights — a line and a latitude · Explained in: Running fix

Course 225° to Mindelo, 20 Nov
  • 0730 LMT · altitude 14° · Zn 119°
  • 0900 LMT · altitude 30° · Zn 134°
  • 1200 LMT · altitude 46° · Zn 185°
  • 1430 LMT · altitude 31° · Zn 226°

You are sailing from the Canaries to Mindelo in the Cape Verdes. Which sight tells you best whether you are left or right of your track?

  1. 1430 — the Sun is ahead, so the line crosses the track
  2. 1200 — the Sun is highest, so the line is most accurate
  3. 0730 — the Sun is lowest, so its bearing is steadiest
  4. 0900 — the Sun is abeam, so the line runs along the track
Show the answer

D. 0900 — the Sun is abeam, so the line runs along the track

Sun abeam (134° ≈ 225° − 90°): the line lies parallel to the course — a course line, showing any offset to either side.

Course and speed lines · Explained in: One line

Practise it

All 100 questions of this topic are in the app: practice by topic with the reason after every answer, your mistakes brought back, and a timed mock exam. Free, no sign-up, in the browser or in Telegram.